(2z-1)(-z^2+3z-4)=

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Solution for (2z-1)(-z^2+3z-4)= equation: 


Simplifying
(2z + -1)(-1z2 + 3z + -4) = 0

Reorder the terms:
(-1 + 2z)(-1z2 + 3z + -4) = 0

Reorder the terms:
(-1 + 2z)(-4 + 3z + -1z2) = 0

Multiply (-1 + 2z) * (-4 + 3z + -1z2)
(-1(-4 + 3z + -1z2) + 2z * (-4 + 3z + -1z2)) = 0
((-4 * -1 + 3z * -1 + -1z2 * -1) + 2z * (-4 + 3z + -1z2)) = 0
((4 + -3z + 1z2) + 2z * (-4 + 3z + -1z2)) = 0
(4 + -3z + 1z2 + (-4 * 2z + 3z * 2z + -1z2 * 2z)) = 0
(4 + -3z + 1z2 + (-8z + 6z2 + -2z3)) = 0

Reorder the terms:
(4 + -3z + -8z + 1z2 + 6z2 + -2z3) = 0

Combine like terms: -3z + -8z = -11z
(4 + -11z + 1z2 + 6z2 + -2z3) = 0

Combine like terms: 1z2 + 6z2 = 7z2
(4 + -11z + 7z2 + -2z3) = 0

Solving
4 + -11z + 7z2 + -2z3 = 0

Solving for variable 'z'.

The solution to this equation could not be determined.

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